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Current File : //proc/2/root/usr/share/zsh/4.3.11/functions/_mkdir

#compdef mkdir

local curcontext="$curcontext" line state \
  args args_zsh args_cmd variant expl ret=1
typeset -a opt_args

args=(
  '(-m --mode)'{-m,--mode=}'[set permission mode]:numeric mode'
  '(-p --parents)'{-p,--parents}'[make parent directories as needed]'
  )

args_zsh=('(-)*: :->directories')

args_cmd=(
  '(-v --verbose)'{-v,--verbose}'[print message for each created directory]'
  '(- :)--help[display help information]'
  '(- :)--version[display version information]'
  '*: :->directories'
  )

case "$OSTYPE" in
  linux*)
    args_cmd=(
      '(-Z --context)'{-Z,--context=}'[set SELinux context]:SELinux context'
      $args_cmd)
    ;;
esac

_pick_variant -r variant gnu=gnu zsh='\(eval\)' unix --help

# It can still happen that there is a precommand command or builtin in the line.
# In such cases, the variant has to be modified suitably, after further checking
# the variant of the _command_ mkdir.

# I currently don't know of any way to find out what precommands are present on
# the line. The variant should be modified like this once a way is found out:

# if [[ $variant == zsh ]]; then
#   if [[ $precommand = *command* ]]; then
#     _mkdir_command () { command mkdir "$@" }
#     _pick_variant -c _mkdir_command -r variant gnu=gnu unix --help
#   fi
# elif [[ $precommand = *builtin* ]]; then
#   variant=zsh
# fi

if [[ $variant == zsh ]]; then
  args+=($args_zsh)
else
  args+=($args_cmd)
fi

# remove long options?
[[ $variant != gnu ]] && args=( ${${${args:#(|*\))--*}//--[^ )]#/}/\( #\)/} )

_arguments -C -s $args && ret=0

case "$state" in
  directories)
    if (( $ret )) && [[ ! -prefix - ]] || \
      [[ $variant == zsh && ${#${${words[2,-1]}:#-*}} -gt 0 ]]; then
      _wanted directories expl \
	'parent directory (alternatively specify name of directory)' \
	_path_files -/ || _message 'name of directory'
      ret=0
    fi
    ;;
esac

return ret

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